MATH SOLVE

4 months ago

Q:
# Hello I need help with some math homework. PLEASE HELP!!! I'll send an attachment.

Accepted Solution

A:

PART 1.

Going westward:

Distance: 2400 miles

Rate (this is speed): (450-wind_speed) mph

Time: distance / speed = 2400 / (450-wind speed)

Going eastward:

Distance: 2400 miles

Rate (this is speed): (450+wind_speed) mph

Time: distance / speed = 2400 / (450+wind speed)

PART 2

Formula for speed:

speed = distance / time

Now we solve this for time:

time = distance / speed

11h = 2400 / (450+-wind_speed)

+- sign is put because in one case wind increases speed of plane and in other case it decreases speed.

PART 3

To solve for wind_speed we start by rearranging formula so that we have wind_speed on left side:

(450+-wind_speed) = 2400 / 11

(450+-wind_speed) = 218mph

To fly this distance in 11h speed of plane must be 218mph.

The only way to get this solution is if we substract wind speed:

450-wind_speed = 218

wind_speed = 450-218 = 232mph

Going westward:

Distance: 2400 miles

Rate (this is speed): (450-wind_speed) mph

Time: distance / speed = 2400 / (450-wind speed)

Going eastward:

Distance: 2400 miles

Rate (this is speed): (450+wind_speed) mph

Time: distance / speed = 2400 / (450+wind speed)

PART 2

Formula for speed:

speed = distance / time

Now we solve this for time:

time = distance / speed

11h = 2400 / (450+-wind_speed)

+- sign is put because in one case wind increases speed of plane and in other case it decreases speed.

PART 3

To solve for wind_speed we start by rearranging formula so that we have wind_speed on left side:

(450+-wind_speed) = 2400 / 11

(450+-wind_speed) = 218mph

To fly this distance in 11h speed of plane must be 218mph.

The only way to get this solution is if we substract wind speed:

450-wind_speed = 218

wind_speed = 450-218 = 232mph