At a hockey game, a vender sold a combined total of 176 sodas and hot dogs. The number of sodas sold was three times the number of hot dogs sold. Find the number of sodas and the number of hot dogs sold.

Answer:Hot dogs sold: 44Sodas sold: 132Step-by-step explanation:This is is a problem of a system of two equations with two unknowns. This can be solved in multiple ways (the substitution method, the elimination method, the equalization method, the graphic method...) . I will resolve it using the equalization method that is a little bit more practical from my point of view. First, we have to determine the system by the data we are given: [tex]\left \{ {{y+x=176} \atop {y=3x}} \right.[/tex]Where:[tex]y=sodas sold\\x=hot dogs sold[/tex]Secondly, we are going to isolate any variable from both equations. I chose to isolate Y. [tex]\left \{ {{y=176-x} \atop {y=3x}} \right.[/tex]Thirdly, we equalizate both equations. [tex]Y= Y[/tex]So we get:[tex]176-x=3x[/tex]Then we isolate X. [tex]-x-3x=-176[/tex][tex]-4x=-176[/tex][tex]x=-176:(-4)[/tex][tex]x=44[/tex]So now we know that the number of hot dogs sold was 44! If the sodas sold were three times the number of hot dogs sold, then we know that there were 132 sodas sold at the hockey game!